rust ⁽¹⁾

To convert `Option<T>` to `Option<&T>` use `as_deref()` To convert `&Option<T>` to `Option<&T>` use `as_deref()` To convert `Option<&T>` to `Option<T>` use `cloned()` I don't know what is the difference between `as_ref()` and `as_deref()` when it comes to converting `&Option<T>` to `Option<&T>`.